$2x^2\; -\;4x\;+\;2y^2\;+12y\;-\;12$ = 0
Divide each term by 2
$x^2\;-2x +\;y^2 + 6y$ - 6 = 0
Complete the squares
(x - 1)2 + (y + 3)2 - 6 = 0
Centre (1,-3)
Radius = $\sqrt{6+(1)^2+(-3)^2}$
= $\sqrt{6+1+9}$ = $\sqrt16\$ = 4 units
johnmulu answered the question on March 8, 2017 at 05:00
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